Asked by Jimmy
determine the volume of 0.250 m H2SO4 needed to react with 5.00 g of zinc to produce H2 and ZnSO4
Answers
Answered by
DrBob222
I'm sure you meant o.250 M. M stands for molarity while m stands for molality. There is a difference.
Zn + H2SO4 ==> ZnSO4 + H2
mols Zn = grams/atomic mass = 5.00/about 65 = about 0.076
From the coefficients you can tell it takes 1 mols H2SO4 for every 1 mole Zn used; therefore, you will need about 0.076 = about 0.076 mols H2SO4.
M H2SO4 = mols/L
0.250 M = 0.076/L. Solve for L and I would convert to mL.
Polst your work if you get stuck. Confirm the atomic mass of Zn and check all the calculations.
Zn + H2SO4 ==> ZnSO4 + H2
mols Zn = grams/atomic mass = 5.00/about 65 = about 0.076
From the coefficients you can tell it takes 1 mols H2SO4 for every 1 mole Zn used; therefore, you will need about 0.076 = about 0.076 mols H2SO4.
M H2SO4 = mols/L
0.250 M = 0.076/L. Solve for L and I would convert to mL.
Polst your work if you get stuck. Confirm the atomic mass of Zn and check all the calculations.
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