Question

A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2
by using the formula 75−16t2
, where t
is time in seconds.(1 point)
s
Remaining Attempts : 3
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Answers

GPT-4o mini
To find the height of the cliff-diver above the ocean after 2 seconds, we can use the given formula:

\[
s(t) = 75 - 16t^2
\]

where \( s(t) \) is the height above the ocean in feet and \( t \) is the time in seconds.

Let's evaluate \( s(2) \):

1. Substitute \( t = 2 \) into the formula:

\[
s(2) = 75 - 16(2^2)
\]

2. Calculate \( 2^2 \):

\[
2^2 = 4
\]

3. Now substitute that value back into the formula:

\[
s(2) = 75 - 16(4)
\]

4. Calculate \( 16 \times 4 \):

\[
16 \times 4 = 64
\]

5. Now substitute that value back into the formula:

\[
s(2) = 75 - 64
\]

6. Perform the subtraction:

\[
s(2) = 11
\]

So, the diver is **11 feet above the ocean** after 2 seconds.