Velocity and Acceleration Quick Check

Question

3 of 53 of 5 Items

Question
Use the equation for motion to answer the question.

x=x0+v0t+12at2


An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?

(1 point)
Responses

30 m
30 m

60 m
60 m

32 m
32 m

17 m
17 m
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Answer 1

To determine the final position of the object after 1 second, we can use the motion equation provided:

$$x=x_0+v_{0}t+\frac{1}{2}a{t}^2$$

Given:

• Starting position ($x_0$) = 2 m
• Starting velocity ($v_0$) = 15 m/s
• Time ($t$) = 1 s
• Acceleration ($a$) = 0 m/s² (constant speed means no acceleration)

Substituting the given values into the equation:

$$x=2,m+(15,m/s)(1,s)+\frac{1}{2}(0,m/s^2)(1,s{)}^2$$

This simplifies to:

$$x=2,m+15,m+0$$

$$x=17,m$$

Therefore, the final position of the object after 1 second is 17 m.