Question

Velocity and Acceleration Quick Check
3 of 53 of 5 Items






Question
Use the equation for motion to answer the question.

x=x0+v0t+12at2


An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?

(1 point)
Responses

30 m
30 m

60 m
60 m

32 m
32 m

17 m
17 m
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Answer 1

To determine the final position of the object after 1 second, we can use the motion equation provided:

\[ x = x_0 + v_0t + \frac{1}{2}at^2 \]

Given:
- Starting position (\( x_0 \)) = 2 m
- Starting velocity (\( v_0 \)) = 15 m/s
- Time (\( t \)) = 1 s
- Acceleration (\( a \)) = 0 m/s² (constant speed means no acceleration)

Substituting the given values into the equation:

\[ x = 2 \, m + (15 \, m/s)(1 \, s) + \frac{1}{2}(0 \, m/s^2)(1 \, s)^2 \]

This simplifies to:

\[ x = 2 \, m + 15 \, m + 0 \]

\[ x = 17 \, m \]

Therefore, the final position of the object after 1 second is **17 m**.