Question

what is the number of atoms in the formula 2Ga(OH)3
GPT-4o mini
To determine the number of atoms in the chemical formula \(2 \text{Ga(OH)}_3\), we can break it down as follows:

1. **Identify the components in the formula:**
- \(2 \text{Ga(OH)}_3\) means there are 2 gallium (Ga) units and each unit has 3 hydroxide (OH) groups.
- Each hydroxide (OH) group contains 1 oxygen (O) atom and 1 hydrogen (H) atom.

2. **Calculate the atoms for each component:**
- For gallium (Ga): There are \(2 \times 1 = 2\) Ga atoms.
- For hydroxide (OH):
- Each \( \text{OH} \) group contributes 1 O and 1 H. Since there are 3 OH groups for each Ga, in total for 2 Ga units we have:
- Oxygen: \(2 \times 3 = 6\) O atoms (from 3 OH groups for each Ga).
- Hydrogen: \(2 \times 3 = 6\) H atoms.

3. **Total the atoms from each component:**
- Total Ga atoms: 2
- Total O atoms: 6
- Total H atoms: 6

Adding these together gives:
\[
2 \text{ (Ga)} + 6 \text{ (O)} + 6 \text{ (H)} = 14 \text{ atoms}
\]

So, the total number of atoms in the formula \(2 \text{Ga(OH)}_3\) is **14 atoms**.
C8HI8
GPT-4o mini
To determine the number of atoms in the chemical formula \( \text{C}_8\text{H}_8\text{I}_8 \), we can break it down as follows:

1. **Identify the components in the formula:**
- **Carbon (C)**: There are 8 carbon atoms.
- **Hydrogen (H)**: There are 8 hydrogen atoms.
- **Iodine (I)**: There are 8 iodine atoms.

2. **Total the atoms:**
- Total Carbon atoms: 8
- Total Hydrogen atoms: 8
- Total Iodine atoms: 8

Adding these together gives:
\[
8 \text{ (C)} + 8 \text{ (H)} + 8 \text{ (I)} = 24 \text{ atoms}
\]

So, the total number of atoms in the formula \( \text{C}_8\text{H}_8\text{I}_8 \) is **24 atoms**.
AgBrO2
GPT-4o mini
To determine the number of atoms in the chemical formula \( \text{AgBrO}_2 \), we analyze its components:

1. **Identify the components in the formula:**
- **Silver (Ag)**: There is 1 silver atom.
- **Bromine (Br)**: There is 1 bromine atom.
- **Oxygen (O)**: There are 2 oxygen atoms.

2. **Total the atoms:**
- Total Silver atoms: 1
- Total Bromine atoms: 1
- Total Oxygen atoms: 2

Adding these together gives:
\[
1 \text{ (Ag)} + 1 \text{ (Br)} + 2 \text{ (O)} = 4 \text{ atoms}
\]

So, the total number of atoms in the formula \( \text{AgBrO}_2 \) is **4 atoms**.
3FeCo(OH)3
GPT-4o mini
To determine the number of atoms in the formula \(3 \text{FeCo(OH)}_3\), we'll analyze each component in the formula:

1. **Identify the components:**
- The formula consists of:
- 3 Iron (Fe) atoms
- 3 Cobalt (Co) atoms
- Each \(\text{OH}\) group contains:
- 1 Oxygen (O) atom
- 1 Hydrogen (H) atom

Since there are 3 \(\text{OH}\) groups for each cobalt atom, we can calculate the total number of oxygen and hydrogen atoms.

2. **Calculate the total number of each type of atom:**
- Total Iron (Fe) atoms: \(3\)
- Total Cobalt (Co) atoms: \(3\)
- Total Hydroxide (\(\text{OH}\)) groups: \(3\) (one for each Co)
- Total Oxygen (O) atoms from \(\text{OH}\): \(3 \times 3 = 9\)
- Total Hydrogen (H) atoms from \(\text{OH}\): \(3 \times 3 = 9\)

3. **Add the total number of atoms:**
- Combined total for Iron: \(3\)
- Combined total for Cobalt: \(3\)
- Combined total for Oxygen: \(3 \times 3 = 9\)
- Combined total for Hydrogen: \(3 \times 3 = 9\)

Now summing these gives:
\[
3 \text{ (Fe)} + 3 \text{ (Co)} + 9 \text{ (O)} + 9 \text{ (H)} = 24 \text{ atoms}
\]

So, the total number of atoms in the formula \(3 \text{FeCo(OH)}_3\) is **24 atoms**.
2C3H8O2
GPT-4o mini
To find the total number of atoms in the chemical formula \(2 \text{C}_3\text{H}_8\text{O}_2\), we will break it down step by step.

1. **Identify the components in the formula:**
- The formula \(2 \text{C}_3\text{H}_8\text{O}_2\) means there are 2 units of \( \text{C}_3\text{H}_8\text{O}_2 \).
- Each unit of \( \text{C}_3\text{H}_8\text{O}_2 \) contains:
- **Carbon (C)**: 3 atoms
- **Hydrogen (H)**: 8 atoms
- **Oxygen (O)**: 2 atoms

2. **Calculate the total number of atoms in one unit:**
- Total C atoms in one unit: \(3\)
- Total H atoms in one unit: \(8\)
- Total O atoms in one unit: \(2\)

3. **Multiply by the coefficient (2 units):**
- Total C atoms: \(2 \times 3 = 6\)
- Total H atoms: \(2 \times 8 = 16\)
- Total O atoms: \(2 \times 2 = 4\)

4. **Sum all the atoms:**
\[
6 \text{ (C)} + 16 \text{ (H)} + 4 \text{ (O)} = 26 \text{ atoms}
\]

Therefore, the total number of atoms in the formula \(2 \text{C}_3\text{H}_8\text{O}_2\) is **26 atoms**.
2NaHpo4
GPT-4o mini
To determine the total number of atoms in the formula \(2 \text{NaHPO}_4\), we can break it down as follows:

1. **Identify the components in the formula:**
- The formula \(2 \text{NaHPO}_4\) means there are 2 units of \( \text{NaHPO}_4 \).
- Each unit of \( \text{NaHPO}_4 \) contains:
- **Sodium (Na)**: 1 atom
- **Hydrogen (H)**: 1 atom
- **Phosphorus (P)**: 1 atom
- **Oxygen (O)**: 4 atoms

2. **Calculate the total number of atoms in one unit:**
- Total Na atoms in one unit: \(1\)
- Total H atoms in one unit: \(1\)
- Total P atoms in one unit: \(1\)
- Total O atoms in one unit: \(4\)

3. **Multiply by the coefficient (2 units):**
- Total Na atoms: \(2 \times 1 = 2\)
- Total H atoms: \(2 \times 1 = 2\)
- Total P atoms: \(2 \times 1 = 2\)
- Total O atoms: \(2 \times 4 = 8\)

4. **Sum all the atoms:**
\[
2 \text{ (Na)} + 2 \text{ (H)} + 2 \text{ (P)} + 8 \text{ (O)} = 14 \text{ atoms}
\]

Therefore, the total number of atoms in the formula \(2 \text{NaHPO}_4\) is **14 atoms**.