Question
what is the number of atoms in the formula C8H18
Answers
GPT-4o mini
The molecular formula \( C_8H_{18} \) represents octane, which consists of:
- 8 carbon (C) atoms
- 18 hydrogen (H) atoms
To find the total number of atoms in the formula, simply add the number of carbon atoms and hydrogen atoms together:
\[
8 \, (\text{C atoms}) + 18 \, (\text{H atoms}) = 26 \, \text{atoms}
\]
So, there are a total of 26 atoms in the formula \( C_8H_{18} \).
- 8 carbon (C) atoms
- 18 hydrogen (H) atoms
To find the total number of atoms in the formula, simply add the number of carbon atoms and hydrogen atoms together:
\[
8 \, (\text{C atoms}) + 18 \, (\text{H atoms}) = 26 \, \text{atoms}
\]
So, there are a total of 26 atoms in the formula \( C_8H_{18} \).
F3No2S
GPT-4o mini
The molecular formula \( \text{F}_3\text{NO}_2\text{S} \) represents a molecule that contains the following atoms:
- 3 fluorine (F) atoms
- 1 nitrogen (N) atom
- 2 oxygen (O) atoms
- 1 sulfur (S) atom
To find the total number of atoms in the formula, add the number of each type of atom together:
\[
3 \, (\text{F}) + 1 \, (\text{N}) + 2 \, (\text{O}) + 1 \, (\text{S}) = 7 \, \text{atoms}
\]
Therefore, there are a total of 7 atoms in the formula \( \text{F}_3\text{NO}_2\text{S} \).
- 3 fluorine (F) atoms
- 1 nitrogen (N) atom
- 2 oxygen (O) atoms
- 1 sulfur (S) atom
To find the total number of atoms in the formula, add the number of each type of atom together:
\[
3 \, (\text{F}) + 1 \, (\text{N}) + 2 \, (\text{O}) + 1 \, (\text{S}) = 7 \, \text{atoms}
\]
Therefore, there are a total of 7 atoms in the formula \( \text{F}_3\text{NO}_2\text{S} \).
4AsCl3
GPT-4o mini
The formula \( 4\text{AsCl}_3 \) indicates that there are 4 units of the chemical compound \( \text{AsCl}_3 \) (arsenic trichloride). To determine the total number of atoms, we first analyze the structure of \( \text{AsCl}_3 \):
- Each molecule of \( \text{AsCl}_3 \) contains:
- 1 arsenic (As) atom
- 3 chlorine (Cl) atoms
Now, for \( 4\text{AsCl}_3 \), the total number of each type of atom can be calculated as follows:
- For arsenic (As):
\[
4 \times 1 = 4 \, \text{As atoms}
\]
- For chlorine (Cl):
\[
4 \times 3 = 12 \, \text{Cl atoms}
\]
Now, adding these together gives:
\[
4 \, (\text{As}) + 12 \, (\text{Cl}) = 16 \, \text{atoms}
\]
Therefore, there are a total of 16 atoms in the formula \( 4\text{AsCl}_3 \).
- Each molecule of \( \text{AsCl}_3 \) contains:
- 1 arsenic (As) atom
- 3 chlorine (Cl) atoms
Now, for \( 4\text{AsCl}_3 \), the total number of each type of atom can be calculated as follows:
- For arsenic (As):
\[
4 \times 1 = 4 \, \text{As atoms}
\]
- For chlorine (Cl):
\[
4 \times 3 = 12 \, \text{Cl atoms}
\]
Now, adding these together gives:
\[
4 \, (\text{As}) + 12 \, (\text{Cl}) = 16 \, \text{atoms}
\]
Therefore, there are a total of 16 atoms in the formula \( 4\text{AsCl}_3 \).
CH3CooNa
GPT-4o mini
The formula \( \text{CH}_3\text{COO}\text{Na} \) represents sodium acetate. To determine the total number of atoms in this formula, we can break it down as follows:
- **Carbon (C)**: There are 2 carbon atoms (one from \( \text{CH}_3 \) and one from \( \text{COO} \)).
- **Hydrogen (H)**: There are 3 hydrogen atoms from \( \text{CH}_3 \) and 1 hydrogen atom from \( \text{COO} \), totaling 4 hydrogen atoms.
- **Oxygen (O)**: There are 2 oxygen atoms in \( \text{COO} \).
- **Sodium (Na)**: There is 1 sodium atom (from \( \text{Na} \)).
Now, let's count the total number of atoms:
- Carbon (C): 2
- Hydrogen (H): 4
- Oxygen (O): 2
- Sodium (Na): 1
Adding these together gives:
\[
2 \, (\text{C}) + 4 \, (\text{H}) + 2 \, (\text{O}) + 1 \, (\text{Na}) = 9 \, \text{atoms}
\]
Therefore, there are a total of **9 atoms** in the formula \( \text{CH}_3\text{COO}\text{Na} \).
- **Carbon (C)**: There are 2 carbon atoms (one from \( \text{CH}_3 \) and one from \( \text{COO} \)).
- **Hydrogen (H)**: There are 3 hydrogen atoms from \( \text{CH}_3 \) and 1 hydrogen atom from \( \text{COO} \), totaling 4 hydrogen atoms.
- **Oxygen (O)**: There are 2 oxygen atoms in \( \text{COO} \).
- **Sodium (Na)**: There is 1 sodium atom (from \( \text{Na} \)).
Now, let's count the total number of atoms:
- Carbon (C): 2
- Hydrogen (H): 4
- Oxygen (O): 2
- Sodium (Na): 1
Adding these together gives:
\[
2 \, (\text{C}) + 4 \, (\text{H}) + 2 \, (\text{O}) + 1 \, (\text{Na}) = 9 \, \text{atoms}
\]
Therefore, there are a total of **9 atoms** in the formula \( \text{CH}_3\text{COO}\text{Na} \).
2Ga(CH)3
GPT-4o mini
The formula \( 2\text{Ga(CH}_3)_3 \) represents a compound where each unit contains gallium (Ga) and three methyl groups (\( \text{CH}_3 \)). To find the total number of atoms, let's break it down:
1. Each \( \text{Ga(CH}_3)_3 \) contains:
- 1 gallium (Ga) atom
- 3 methyl groups, and each methyl group (\( \text{CH}_3 \)) contains:
- 1 carbon (C) atom
- 3 hydrogen (H) atoms
So, for each \( \text{CH}_3 \), we have:
- 3 carbon atoms total from 3 methyl groups (1 C from each of the 3)
- 9 hydrogen atoms total from 3 methyl groups (3 H from each of the 3)
Now, we can summarize the atoms per formula unit of \( \text{Ga(CH}_3)_3 \):
- **Gallium (Ga)**: 1
- **Carbon (C)**: 3
- **Hydrogen (H)**: 9
Now, if we multiply by 2 (since we have \( 2\text{Ga(CH}_3)_3 \)):
- **Gallium (Ga)**: \( 2 \times 1 = 2 \)
- **Carbon (C)**: \( 2 \times 3 = 6 \)
- **Hydrogen (H)**: \( 2 \times 9 = 18 \)
Now adding these totals gives:
\[
2 \, (\text{Ga}) + 6 \, (\text{C}) + 18 \, (\text{H}) = 26 \, \text{atoms}
\]
Therefore, there are a total of **26 atoms** in the formula \( 2\text{Ga(CH}_3)_3 \).
1. Each \( \text{Ga(CH}_3)_3 \) contains:
- 1 gallium (Ga) atom
- 3 methyl groups, and each methyl group (\( \text{CH}_3 \)) contains:
- 1 carbon (C) atom
- 3 hydrogen (H) atoms
So, for each \( \text{CH}_3 \), we have:
- 3 carbon atoms total from 3 methyl groups (1 C from each of the 3)
- 9 hydrogen atoms total from 3 methyl groups (3 H from each of the 3)
Now, we can summarize the atoms per formula unit of \( \text{Ga(CH}_3)_3 \):
- **Gallium (Ga)**: 1
- **Carbon (C)**: 3
- **Hydrogen (H)**: 9
Now, if we multiply by 2 (since we have \( 2\text{Ga(CH}_3)_3 \)):
- **Gallium (Ga)**: \( 2 \times 1 = 2 \)
- **Carbon (C)**: \( 2 \times 3 = 6 \)
- **Hydrogen (H)**: \( 2 \times 9 = 18 \)
Now adding these totals gives:
\[
2 \, (\text{Ga}) + 6 \, (\text{C}) + 18 \, (\text{H}) = 26 \, \text{atoms}
\]
Therefore, there are a total of **26 atoms** in the formula \( 2\text{Ga(CH}_3)_3 \).
2NaH2Po4
GPT-4o mini
The formula \( 2\text{NaH}_2\text{PO}_4 \) represents two units of sodium dihydrogen phosphate. Let's break down the number of each type of atom in one unit of \( \text{NaH}_2\text{PO}_4 \):
### Composition of NaH₂PO₄:
- **Sodium (Na)**: 1 atom
- **Hydrogen (H)**: 2 atoms
- **Phosphorus (P)**: 1 atom
- **Oxygen (O)**: 4 atoms
### Total atoms in one unit:
Adding these together gives:
\[
1 \, (\text{Na}) + 2 \, (\text{H}) + 1 \, (\text{P}) + 4 \, (\text{O}) = 8 \, \text{atoms}
\]
### Now multiply by 2:
Since we have \( 2\text{NaH}_2\text{PO}_4 \), we will multiply each component by 2:
- **Sodium (Na)**: \( 2 \times 1 = 2 \)
- **Hydrogen (H)**: \( 2 \times 2 = 4 \)
- **Phosphorus (P)**: \( 2 \times 1 = 2 \)
- **Oxygen (O)**: \( 2 \times 4 = 8 \)
### Total atoms:
Now adding these together gives:
\[
2 \, (\text{Na}) + 4 \, (\text{H}) + 2 \, (\text{P}) + 8 \, (\text{O}) = 16 \, \text{atoms}
\]
Therefore, there are a total of **16 atoms** in the formula \( 2\text{NaH}_2\text{PO}_4 \).
### Composition of NaH₂PO₄:
- **Sodium (Na)**: 1 atom
- **Hydrogen (H)**: 2 atoms
- **Phosphorus (P)**: 1 atom
- **Oxygen (O)**: 4 atoms
### Total atoms in one unit:
Adding these together gives:
\[
1 \, (\text{Na}) + 2 \, (\text{H}) + 1 \, (\text{P}) + 4 \, (\text{O}) = 8 \, \text{atoms}
\]
### Now multiply by 2:
Since we have \( 2\text{NaH}_2\text{PO}_4 \), we will multiply each component by 2:
- **Sodium (Na)**: \( 2 \times 1 = 2 \)
- **Hydrogen (H)**: \( 2 \times 2 = 4 \)
- **Phosphorus (P)**: \( 2 \times 1 = 2 \)
- **Oxygen (O)**: \( 2 \times 4 = 8 \)
### Total atoms:
Now adding these together gives:
\[
2 \, (\text{Na}) + 4 \, (\text{H}) + 2 \, (\text{P}) + 8 \, (\text{O}) = 16 \, \text{atoms}
\]
Therefore, there are a total of **16 atoms** in the formula \( 2\text{NaH}_2\text{PO}_4 \).