Question

The question asked... Calculate the solubility of calcium sulfate in grams solute per 100 grams solvent. Assume that the volume occupied by the solute in the solution in negligibly small. I solved and got 4.9 x 10 ^-3 mol/L... how do I put this in grams solute per 100 grams solvent?

Answer 1

M = moles/L.
moles = g/molar mass. You know molar mass and you know moles, solve for grams. That, of course, will be grams/L and you take 1/10 of that to obtain g/100 mL of solution which is g/100 mL solvent IF the mass solute is very small.

Answer 2

I came up with 6.67 x 10^-3 g solute/ 100g solvent. Based on the information in the problem, does this seem about right?

Answer 3

I don't know what you used for Ksp; however, based on your answer of 4.9 x 10^-3 moles/L, I think it should be more like 0.0667.
0.0049 x 136 something = 0.666 g/L and 1/10 that is 0.0667.