Question

What is the average of these numbers
2,6,9,5,2,41,8
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Answer 1

To find the average of a set of numbers, you need to follow these steps:

1. **Sum the numbers**: Add all the numbers together.
2. **Count the numbers**: Determine how many numbers there are.
3. **Divide the sum by the count**: This gives you the average.

Let's go through the calculations using the numbers you provided: 2, 6, 9, 5, 2, 41, and 8.

### Step 1: Sum the numbers
- \( 2 + 6 + 9 + 5 + 2 + 41 + 8 \)
- Calculate the sum step-by-step:
- \( 2 + 6 = 8 \)
- \( 8 + 9 = 17 \)
- \( 17 + 5 = 22 \)
- \( 22 + 2 = 24 \)
- \( 24 + 41 = 65 \)
- \( 65 + 8 = 73 \)

So, the total sum is **73**.

### Step 2: Count the numbers
The numbers given are: 2, 6, 9, 5, 2, 41, and 8, which makes a total of **7 numbers**.

### Step 3: Divide the sum by the count
Now, divide the sum (73) by the count (7):
\[
\text{Average} = \frac{\text{Sum}}{\text{Count}} = \frac{73}{7} \approx 10.42857
\]

Thus, the average of the numbers 2, 6, 9, 5, 2, 41, and 8 is approximately **10.43** (to two decimal places).