360*5-sum2= sumlastthree
1800-201=
1599 = sumlast three
But all have to be greater than 102
so let the first two be 102, 103, lowest that they can be.
1599-102-103= last digit.
so figure the last digit.
1800-201=
1599 = sumlast three
But all have to be greater than 102
so let the first two be 102, 103, lowest that they can be.
1599-102-103= last digit.
so figure the last digit.
Step 1: Calculate the sum of the five integers.
Since the average of the five integers is 360, we can multiply the average by 5 to find the sum:
Sum of the five integers = 360 * 5 = 1800.
Step 2: Subtract the sum of the four known integers.
The sum of the four known integers is 99 + 102 + x1 + x2, where x1 and x2 represent the remaining two unknown integers.
1800 - (99 + 102 + x1 + x2) = 1800 - (201 + x1 + x2) = 1800 - (201 + x1 + x2).
Step 3: Simplify the equation and solve for the maximum value of x1 + x2.
1800 - (201 + x1 + x2) = 1599 - (x1 + x2).
To maximize the value of x1 + x2, we need to minimize the value of 1599. Therefore, the largest possible integer in the set is 1599.
So, the largest possible integer in the set is 1599.