Question
The average of a set of five different positive integers is 360. The two smallest integers in the set are 99 and 102. What is the largest possible integer in this set?
Answers
bobpursley
360*5-sum2= sumlastthree
1800-201=
1599 = sumlast three
But all have to be greater than 102
so let the first two be 102, 103, lowest that they can be.
1599-102-103= last digit.
so figure the last digit.
1800-201=
1599 = sumlast three
But all have to be greater than 102
so let the first two be 102, 103, lowest that they can be.
1599-102-103= last digit.
so figure the last digit.