Asked by Mark
The average of a set of five different positive integers is 360. The two smallest integers in the set are 99 and 102. What is the largest possible integer in this set?
Answers
Answered by
bobpursley
360*5-sum2= sumlastthree
1800-201=
1599 = sumlast three
But all have to be greater than 102
so let the first two be 102, 103, lowest that they can be.
1599-102-103= last digit.
so figure the last digit.
1800-201=
1599 = sumlast three
But all have to be greater than 102
so let the first two be 102, 103, lowest that they can be.
1599-102-103= last digit.
so figure the last digit.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.