Question
Question 15
If a car starts at rest and accelerates to 40 m/s in a time of 10 s. What is the acceleration of the car?
\large acceleration=\frac{v_{final}-v_{initial}}{time}
a
4 m/s2
b
4 m/s
c
-4 m/s2
d
400 m/s2
If a car starts at rest and accelerates to 40 m/s in a time of 10 s. What is the acceleration of the car?
\large acceleration=\frac{v_{final}-v_{initial}}{time}
a
4 m/s2
b
4 m/s
c
-4 m/s2
d
400 m/s2
Answers
Answered by
GPT-4o mini
To find the acceleration of the car, you can use the formula:
\[
\text{acceleration} = \frac{v_{final} - v_{initial}}{time}
\]
Given that the car starts at rest, we have:
- \( v_{initial} = 0 \, \text{m/s} \)
- \( v_{final} = 40 \, \text{m/s} \)
- \( time = 10 \, \text{s} \)
Now plugging in the values:
\[
\text{acceleration} = \frac{40 \, \text{m/s} - 0 \, \text{m/s}}{10 \, \text{s}} = \frac{40 \, \text{m/s}}{10 \, \text{s}} = 4 \, \text{m/s}^2
\]
Thus, the acceleration of the car is \( 4 \, \text{m/s}^2 \).
The correct answer is:
**a) 4 m/s²**
\[
\text{acceleration} = \frac{v_{final} - v_{initial}}{time}
\]
Given that the car starts at rest, we have:
- \( v_{initial} = 0 \, \text{m/s} \)
- \( v_{final} = 40 \, \text{m/s} \)
- \( time = 10 \, \text{s} \)
Now plugging in the values:
\[
\text{acceleration} = \frac{40 \, \text{m/s} - 0 \, \text{m/s}}{10 \, \text{s}} = \frac{40 \, \text{m/s}}{10 \, \text{s}} = 4 \, \text{m/s}^2
\]
Thus, the acceleration of the car is \( 4 \, \text{m/s}^2 \).
The correct answer is:
**a) 4 m/s²**