Asked by T.
A 75 kg box starts from the top of a ramp at point A. The coeff of fric. between surface & box is 0.275. The avg. normal force of the surface on the box (while it is on the ramp) is 3/4 of its weight.
A) What is the velocity of the box right before it hits the spring at point B?
B.) If the spring constant is 400 N/m, how far will it compress the spring?
C.) What minimum velocity must the box have at point A in order to ensure it will make the entire way back up the ramp.
A) What is the velocity of the box right before it hits the spring at point B?
B.) If the spring constant is 400 N/m, how far will it compress the spring?
C.) What minimum velocity must the box have at point A in order to ensure it will make the entire way back up the ramp.
Answers
Answered by
bobpursley
How far is it along the ramp from A to the spring at B?
Answered by
T.
R=25
This is from Point A with a curve going to the right (if that makes any sense) .The ramp is 30 m.
This is from Point A with a curve going to the right (if that makes any sense) .The ramp is 30 m.
Answered by
bobpursley
net force=mass*acceleration
1/4*mg-3/4*mu*mg=m*acceleration
knowing acceleration..
vf^2=2*a*distance
solve for vf
1/2 m vf^2=1/2 k x solve for x, the distance the spring is compressed. I can't tell, but I assume no friction the last five meters, if there is, you have to figure that in.
1/4*mg-3/4*mu*mg=m*acceleration
knowing acceleration..
vf^2=2*a*distance
solve for vf
1/2 m vf^2=1/2 k x solve for x, the distance the spring is compressed. I can't tell, but I assume no friction the last five meters, if there is, you have to figure that in.
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