Start by multiplying the left side of the equation by 2 to get rid of the fraction on the left side of the equation.

2
3

(4+3b)
=
2+2b

2 ·
2
3

(4+3b)
=
2 · (2+2b)

(4+3b)
=
?

1 answer

To solve the equation by multiplying both sides by 2, we will start with:

\[ \frac{2}{3}(4 + 3b) = 2 + 2b \]

Multiply both sides by 2:

\[ 2 \cdot \frac{2}{3}(4 + 3b) = 2 \cdot (2 + 2b) \]

This simplifies to:

\[ \frac{4}{3}(4 + 3b) = 4 + 4b \]

Now, to get rid of the fraction, we multiply both sides by 3. The equation then becomes:

\[ 4(4 + 3b) = 3(4 + 4b) \]

Now, let's expand both sides:

\[ 16 + 12b = 12 + 12b \]

Next, we'll isolate the variable. We can subtract \(12b\) from both sides:

\[ 16 = 12 \]

This is an inconsistency, which implies that there is no solution to the original equation since we derived a contradiction.

Thus, the final result of the left side simplifies out as demonstrated, but there is no solution when fully solved—indicating the two sides are unequal.