Asked by crissy
I need help on multiplying and dividing functions. I've seen videos and read and read examples but I still don't get it. I did the last problem which looked like an example I had read but I still don't know if I did it right: f(x)=2x+1
g(x)=3X+2
F(3)/g(2)= F(3)=2(3)+1=7
G(2)=3(2)+2=8
f(3)/g(2)=7/8=0.875
seems wrong, I did one more and I got this: f(x)=2x
g(x)=3x^3
f(x)/g(x)=f(x)=2(x)
g(x)=3x^3
then from there I don't know what to do or even if I did it right. Can anyone help me solve these and I'll use them as examples for the rest.
g(x)=3X+2
F(3)/g(2)= F(3)=2(3)+1=7
G(2)=3(2)+2=8
f(3)/g(2)=7/8=0.875
seems wrong, I did one more and I got this: f(x)=2x
g(x)=3x^3
f(x)/g(x)=f(x)=2(x)
g(x)=3x^3
then from there I don't know what to do or even if I did it right. Can anyone help me solve these and I'll use them as examples for the rest.
Answers
Answered by
Reiny
f(x) = 2x+1 , g(x) = 3x+2
f(3) / f(2) = 7/8
then if
f(x)=2x , g(x)=3x^3
f(x)/g(x)=2x/(3x^3) = 2/3x^2
end of problem, how easy was that
Answered by
Steve
Note that f(2) does not mean f*2 where f has some intrinsic value.
If f(x) = 2x+1
f(2) is a signle number, obtained by replacing all the x's with 2's:
f(2) = 2*2+1 = 5
The confusion arises due to using () both for multiplication of numbers and containing the argument of a function.
f(2) is read <b> f of 2</b>, nit f times 2.
If f(x) = 2x+1
f(2) is a signle number, obtained by replacing all the x's with 2's:
f(2) = 2*2+1 = 5
The confusion arises due to using () both for multiplication of numbers and containing the argument of a function.
f(2) is read <b> f of 2</b>, nit f times 2.
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