Question
What is the oxidation charge of the cobalt ion in the compound Co2S3?
Responses
-3
-3
+2
+2
-2
-2
+3
Responses
-3
-3
+2
+2
-2
-2
+3
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine the oxidation charge of the cobalt ion in the compound Co₂S₃, we can analyze the charges of the ions involved.
1. **Sulfide Ion (S²⁻)**: Each sulfide ion has an oxidation state of -2. In Co₂S₃, there are three sulfide ions, so the total contribution from sulfur is:
\[
3 \times (-2) = -6
\]
2. **Cobalt Ion (Co)**: Let the oxidation state of cobalt be \( x \). Since there are two cobalt ions, the total contribution from cobalt is \( 2x \).
3. **Charge Balance**: The compound is neutral, so the sum of the oxidation states must equal zero:
\[
2x + (-6) = 0
\]
Simplifying this gives:
\[
2x = 6 \\
x = +3
\]
Thus, the oxidation charge of the cobalt ion in Co₂S₃ is **+3**.
1. **Sulfide Ion (S²⁻)**: Each sulfide ion has an oxidation state of -2. In Co₂S₃, there are three sulfide ions, so the total contribution from sulfur is:
\[
3 \times (-2) = -6
\]
2. **Cobalt Ion (Co)**: Let the oxidation state of cobalt be \( x \). Since there are two cobalt ions, the total contribution from cobalt is \( 2x \).
3. **Charge Balance**: The compound is neutral, so the sum of the oxidation states must equal zero:
\[
2x + (-6) = 0
\]
Simplifying this gives:
\[
2x = 6 \\
x = +3
\]
Thus, the oxidation charge of the cobalt ion in Co₂S₃ is **+3**.
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