Ask a New Question

Question

evaluate the intergral using substitution
ingergral[(x^2-e^3x)/(x^3-e^3x)^2]dx
15 years ago

Answers

Reiny
By the "Just Look-at-it Theorem and Knowing your Derivatives" and knowing the derivative of ln(...)
I noticed that the derivative of the bottom would be
3(x^2 - e^3x) , which just happens to look awfully close to the top

so if y' = [(x^2-e^3x)/(x^3-e^3x)^2] then

y = (1/3)(ln(x^3 - e^3x))
15 years ago

Related Questions

For the intergral of -(x^2)/3 +6 interval [0,3] Rewrite it as a function of n using the right ha... For the intergral of -(x^2)/3 +6 interval [0,3] Rewrite it as a function of n using the right ha... intergral of (x^3 -4x + 3)/(2x) dx would this be ln abs(x^3-4x+3) + C? I don't really understa... the intergral (10 4 (2x^2+3x+1)dx i have to find the sum of the intergral using righ... What is the intergral of: 2x/[(x+1)^3] dx Can someone show me how to work to work it... Intergral (27-9x^2)^(1/2) fit to theorem (a^2-u^2)^(1/2) Intergral from -2 to 2 (-2 is at the bottom of the integral sign and 2 is at the top) x^-2dx = -x^-1... intergral 2x^2/(x^2+4x+8) Find the intergral of (1+x)/sqrt(3-x^2) Evaluate the intergral root(xdx).... Help plz show work...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use