Question
                Solve the following system of equations using the elimination method.
0.1x+0.3y=0.9
, 0.1x−0.3y=0.2
(1 point)
Responses
(112,−76)
left parenthesis Start Fraction 11 over 2 End Fraction comma negative Start Fraction 7 over 6 End Fraction right parenthesis
(−76,112)
left parenthesis negative Start Fraction 7 over 6 End Fraction comma Start Fraction 11 over 2 End Fraction right parenthesis
There is no solution
There is no solution
(112,76)
            
        0.1x+0.3y=0.9
, 0.1x−0.3y=0.2
(1 point)
Responses
(112,−76)
left parenthesis Start Fraction 11 over 2 End Fraction comma negative Start Fraction 7 over 6 End Fraction right parenthesis
(−76,112)
left parenthesis negative Start Fraction 7 over 6 End Fraction comma Start Fraction 11 over 2 End Fraction right parenthesis
There is no solution
There is no solution
(112,76)
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To solve the system of equations using the elimination method, we start by rewriting the equations:
1. \( 0.1x + 0.3y = 0.9 \) (Equation 1)
2. \( 0.1x - 0.3y = 0.2 \) (Equation 2)
Next, we can eliminate the decimals for simplicity. We can multiply both equations by 10 to eliminate the decimals:
1. \( x + 3y = 9 \) (Equation 1 multiplied by 10)
2. \( x - 3y = 2 \) (Equation 2 multiplied by 10)
Next, we can use the elimination method. We can subtract Equation 2 from Equation 1:
\[
(x + 3y) - (x - 3y) = 9 - 2
\]
Simplifying, we get:
\[
x + 3y - x + 3y = 7
\]
This simplifies to:
\[
6y = 7
\]
Now, we can solve for \( y \):
\[
y = \frac{7}{6}
\]
Now that we have \( y \), we can substitute it back into either of the original equations to solve for \( x \). Let's substitute \( y \) into Equation 1:
\[
x + 3\left(\frac{7}{6}\right) = 9
\]
This simplifies to:
\[
x + \frac{21}{6} = 9
\]
Now we can convert 9 to a fraction with a denominator of 6:
\[
x + \frac{21}{6} = \frac{54}{6}
\]
Now, isolate \( x \):
\[
x = \frac{54}{6} - \frac{21}{6} = \frac{33}{6} = \frac{11}{2}
\]
Thus, we have found \( x = \frac{11}{2} \) and \( y = \frac{7}{6} \).
The solution to the system of equations is:
\[
\left( \frac{11}{2}, \frac{7}{6} \right)
\]
Therefore, the response from the provided options that matches our solution is:
**left parenthesis Start Fraction 11 over 2 End Fraction comma Start Fraction 7 over 6 End Fraction right parenthesis**.
    
1. \( 0.1x + 0.3y = 0.9 \) (Equation 1)
2. \( 0.1x - 0.3y = 0.2 \) (Equation 2)
Next, we can eliminate the decimals for simplicity. We can multiply both equations by 10 to eliminate the decimals:
1. \( x + 3y = 9 \) (Equation 1 multiplied by 10)
2. \( x - 3y = 2 \) (Equation 2 multiplied by 10)
Next, we can use the elimination method. We can subtract Equation 2 from Equation 1:
\[
(x + 3y) - (x - 3y) = 9 - 2
\]
Simplifying, we get:
\[
x + 3y - x + 3y = 7
\]
This simplifies to:
\[
6y = 7
\]
Now, we can solve for \( y \):
\[
y = \frac{7}{6}
\]
Now that we have \( y \), we can substitute it back into either of the original equations to solve for \( x \). Let's substitute \( y \) into Equation 1:
\[
x + 3\left(\frac{7}{6}\right) = 9
\]
This simplifies to:
\[
x + \frac{21}{6} = 9
\]
Now we can convert 9 to a fraction with a denominator of 6:
\[
x + \frac{21}{6} = \frac{54}{6}
\]
Now, isolate \( x \):
\[
x = \frac{54}{6} - \frac{21}{6} = \frac{33}{6} = \frac{11}{2}
\]
Thus, we have found \( x = \frac{11}{2} \) and \( y = \frac{7}{6} \).
The solution to the system of equations is:
\[
\left( \frac{11}{2}, \frac{7}{6} \right)
\]
Therefore, the response from the provided options that matches our solution is:
**left parenthesis Start Fraction 11 over 2 End Fraction comma Start Fraction 7 over 6 End Fraction right parenthesis**.
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