Question

solve the following system of equations by elimination .

-4x - 8y = 20
8x + 3y = 1

Answer 1

wrong

Answer 2

still wrong

Answer 3

STIL WRONG

Answer 4

WRONGGGGGGGGGGGGGGGGGGGGGGGG

Answer 5

To solve this system of equations by elimination, we can multiply the first equation by 2 to make the coefficients of x in both equations equal and then add the two equations together to eliminate x.

-4x - 8y = 20 (multiply by 2)
8x + 3y = 1

-8x - 16y = 40
8x + 3y = 1

Now, add the two equations together:

-13y = 41

Now, solve for y:

y = -41/13

Next, substitute this value back into one of the original equations to solve for x. Let's use the first equation:

-4x - 8(-41/13) = 20
-4x + 328/13 = 20
-4x = 20 - 328/13
-4x = 260/13 - 328/13
-4x = -68/13
x = 68/52
x = 17/13

Therefore, the solution to the system of equations is x = 17/13 and y = -41/13.

Answer 6

Let's try solving the system of equations by elimination again:

-4x - 8y = 20
8x + 3y = 1

We can multiply the first equation by 2 and the second equation by 1 to make the coefficients of x the same.

-8x - 16y = 40
8x + 3y = 1

Now, add the two equations together:

-13y = 41
y = -41/13

Now, substitute y = -41/13 back into the first equation:

-4x - 8(-41/13) = 20
-4x + 328/13 = 20
-4x = 260/13 - 328/13
-4x = -68/13
x = 17/13

Therefore, the correct solution to the system of equations is x = 17/13 and y = -41/13.

Answer 7

My apologies for the error in my previous responses. Let's solve the system of equations again using the elimination method.

Given equations:
-4x - 8y = 20
8x + 3y = 1

To eliminate y, we can multiply the first equation by 3 and the second equation by 8:

-12x - 24y = 60
64x + 24y = 8

Now, add the two equations together:

52x = 68

Dividing by 52 on both sides gives x = 68 / 52 = 17 / 13

Now substitute x back into one of the original equations to solve for y. Using the second equation:

8(17/13) + 3y = 1
136/13 + 3y = 1
3y = 1 - 136/13
3y = 13/13 - 136/13
3y = -123/13
y = -123 / 39 = -41/13

Therefore, the solution to the system of equations is x = 17/13 and y = -41/13.

Answer 8

Apologies for the errors in my previous responses. Let's correct it and solve the system of equations using the elimination method again.

Given equations:
-4x - 8y = 20
8x + 3y = 1

To eliminate x, we can multiply the first equation by 2 and the second equation by 1:

-8x - 16y = 40
8x + 3y = 1

Now, add the two equations together to eliminate x:

-13y = 41
y = -41/13

Now, substitute y = -41/13 back into the second equation to solve for x:

8x + 3(-41/13) = 1
8x - 123/13 = 1
8x = 13/13 + 123/13
8x = 136/13
x = 17/13

Therefore, the correct solution to the system of equations is x = 17/13 and y = -41/13.

Answer 9

I apologize for the mistakes in my previous responses. Let's solve the system of equations correctly using the elimination method.

Given equations:
-4x - 8y = 20
8x + 3y = 1

Multiply the first equation by 1 and the second equation by 2:
-4x - 8y = 20
16x + 6y = 2

Now, add the two equations together:

-4x + 16x - 8y + 6y = 20 + 2
12x - 2y = 22

Divide the equation by 2 to simplify:

6x - y = 11

Now, add the new equation with the first equation:
-4x - 8y = 20
6x - y = 11

This results in:
2x - 9y = 31

Now we have a new system of equations:
2x - 9y = 31
6x - y = 11

Multiply the second equation by 9:
2x - 9y = 31
54x - 9y = 99

Subtract the first equation from the second equation:
52x = 68
x = 68/52
x = 17/13

Substitute x back into the second equation to solve for y:
6(17/13) - y = 11
102/13 - y = 11
-y = 11 - 102/13
-y = 143/13 - 102/13
-y = 41/13
y = -41/13

Thus, the correct solution is x = 17/13 and y = -41/13. Thank you for your patience.