Asked by olexandra
How to calculate enthalpy change of the following reaction? :
S + 2h2o >>> so2 + 2h2
given: s+o2 >>> so2 - enthalpy change = -296.8 kJ
h2 + 1/2o2 >> h20 enthalpy change= -285.8kj
I was trying to solve it myself but i got confused.. i know i have to change the second equation to opposite side, but do i also multiply any of these equations by 2?
Thank you, I appreciate your help!
S + 2h2o >>> so2 + 2h2
given: s+o2 >>> so2 - enthalpy change = -296.8 kJ
h2 + 1/2o2 >> h20 enthalpy change= -285.8kj
I was trying to solve it myself but i got confused.. i know i have to change the second equation to opposite side, but do i also multiply any of these equations by 2?
Thank you, I appreciate your help!
Answers
Answered by
DrBob222
Reverse equation 2 and multiply it by 2.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.