Asked by Lay
Calculate the enthalpy of the reaction of boron trioxide with steam: B2O3(s) + 3H2O(g) → 3O2(g) + B2H6(g)
Given:
H2O(l)
H2(g) + 1⁄2 O2(g)
2B(s) + 3H2(g)
2B(s) + 3/2 O2(g) → B2O3(s)
→ H2O(g) → H2O(l) → B2H6(g)
44 kJ/mol -286 kJ/mol 36 kJ/mol -1273 kJ/mol
Given:
H2O(l)
H2(g) + 1⁄2 O2(g)
2B(s) + 3H2(g)
2B(s) + 3/2 O2(g) → B2O3(s)
→ H2O(g) → H2O(l) → B2H6(g)
44 kJ/mol -286 kJ/mol 36 kJ/mol -1273 kJ/mol
Answers
Answered by
DrBob222
dHrxn = (n*dHf products) - (n*dHf reactants)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.