For the function​ f, find​ (a) ​f(5​), ​(b) ​f(0​), ​(c) ​f(minus7​), ​(d) f left parenthesis one half right parenthesis

Question

​, and​ (e) f left parenthesis negative one fifth right parenthesis
.
​f(x)equals4xplus3

Answer 1

To find the values of the function \( f(x) = 4x + 3 \) at the specified points, we can substitute the given x-values into the function.

(a) To find \( f(5) \): \[ f(5) = 4(5) + 3 = 20 + 3 = 23 \]

(b) To find \( f(0) \): \[ f(0) = 4(0) + 3 = 0 + 3 = 3 \]

(c) To find \( f(-7) \): \[ f(-7) = 4(-7) + 3 = -28 + 3 = -25 \]

(d) To find \( f\left(\frac{1}{2}\right) \): \[ f\left(\frac{1}{2}\right) = 4\left(\frac{1}{2}\right) + 3 = 2 + 3 = 5 \]

(e) To find \( f\left(-\frac{1}{5}\right) \): \[ f\left(-\frac{1}{5}\right) = 4\left(-\frac{1}{5}\right) + 3 = -\frac{4}{5} + 3 = -\frac{4}{5} + \frac{15}{5} = \frac{11}{5} \]

Summarizing the results:

• (a) \( f(5) = 23 \)
• (b) \( f(0) = 3 \)
• (c) \( f(-7) = -25 \)
• (d) \( f\left(\frac{1}{2}\right) = 5 \)
• (e) \( f\left(-\frac{1}{5}\right) = \frac{11}{5} \)

Answer 2

f(5)=what. That's literally the question

Answer 3

Apologies for any confusion! Here is the direct answer to your question:

For the function \( f(x) = 4x + 3 \):

(a) \( f(5) = 23 \)

If you need further calculations or clarifications, feel free to ask!