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For the function f, find (a) f(5), (b) f(0), (c) f(minus7), (d) f left parenthesis one half right parenthesis , and...Asked by vivi chang
For the function f, find (a) f(5), (b) f(0), (c) f(minus7), (d) f left parenthesis one half right parenthesis
, and (e) f left parenthesis negative one fifth right parenthesis
.
f(x)equals4xplus3
literal question is f(1/2)=what
, and (e) f left parenthesis negative one fifth right parenthesis
.
f(x)equals4xplus3
literal question is f(1/2)=what
Answers
Answered by
vivi chang
no
Answered by
GPT-4o mini
To evaluate the function \( f(x) = 4x + 3 \) for the various values of \( x \), we will substitute each value into the function.
(a) To find \( f(5) \):
\[
f(5) = 4(5) + 3 = 20 + 3 = 23
\]
(b) To find \( f(0) \):
\[
f(0) = 4(0) + 3 = 0 + 3 = 3
\]
(c) To find \( f(-7) \):
\[
f(-7) = 4(-7) + 3 = -28 + 3 = -25
\]
(d) To find \( f\left(\frac{1}{2}\right) \):
\[
f\left(\frac{1}{2}\right) = 4\left(\frac{1}{2}\right) + 3 = 2 + 3 = 5
\]
(e) To find \( f\left(-\frac{1}{5}\right) \):
\[
f\left(-\frac{1}{5}\right) = 4\left(-\frac{1}{5}\right) + 3 = -\frac{4}{5} + 3 = -\frac{4}{5} + \frac{15}{5} = \frac{11}{5}
\]
In summary:
- \( f(5) = 23 \)
- \( f(0) = 3 \)
- \( f(-7) = -25 \)
- \( f\left(\frac{1}{2}\right) = 5 \)
- \( f\left(-\frac{1}{5}\right) = \frac{11}{5} \)
(a) To find \( f(5) \):
\[
f(5) = 4(5) + 3 = 20 + 3 = 23
\]
(b) To find \( f(0) \):
\[
f(0) = 4(0) + 3 = 0 + 3 = 3
\]
(c) To find \( f(-7) \):
\[
f(-7) = 4(-7) + 3 = -28 + 3 = -25
\]
(d) To find \( f\left(\frac{1}{2}\right) \):
\[
f\left(\frac{1}{2}\right) = 4\left(\frac{1}{2}\right) + 3 = 2 + 3 = 5
\]
(e) To find \( f\left(-\frac{1}{5}\right) \):
\[
f\left(-\frac{1}{5}\right) = 4\left(-\frac{1}{5}\right) + 3 = -\frac{4}{5} + 3 = -\frac{4}{5} + \frac{15}{5} = \frac{11}{5}
\]
In summary:
- \( f(5) = 23 \)
- \( f(0) = 3 \)
- \( f(-7) = -25 \)
- \( f\left(\frac{1}{2}\right) = 5 \)
- \( f\left(-\frac{1}{5}\right) = \frac{11}{5} \)
Answered by
GPT-4o mini
I apologize if my response didn't meet your expectations. Let’s go through the evaluations of the function \( f(x) = 4x + 3 \) step-by-step once more.
(a) **Finding \( f(5) \):**
\[
f(5) = 4(5) + 3 = 20 + 3 = 23
\]
(b) **Finding \( f(0) \):**
\[
f(0) = 4(0) + 3 = 0 + 3 = 3
\]
(c) **Finding \( f(-7) \):**
\[
f(-7) = 4(-7) + 3 = -28 + 3 = -25
\]
(d) **Finding \( f\left(\frac{1}{2}\right) \):**
\[
f\left(\frac{1}{2}\right) = 4\left(\frac{1}{2}\right) + 3 = 2 + 3 = 5
\]
(e) **Finding \( f\left(-\frac{1}{5}\right) \):**
\[
f\left(-\frac{1}{5}\right) = 4\left(-\frac{1}{5}\right) + 3 = -\frac{4}{5} + 3 = -\frac{4}{5} + \frac{15}{5} = \frac{11}{5}
\]
### Final results:
- \( f(5) = 23 \)
- \( f(0) = 3 \)
- \( f(-7) = -25 \)
- \( f\left(\frac{1}{2}\right) = 5 \)
- \( f\left(-\frac{1}{5}\right) = \frac{11}{5} \)
If there is an error or something specific you would like to understand more clearly, please let me know!
(a) **Finding \( f(5) \):**
\[
f(5) = 4(5) + 3 = 20 + 3 = 23
\]
(b) **Finding \( f(0) \):**
\[
f(0) = 4(0) + 3 = 0 + 3 = 3
\]
(c) **Finding \( f(-7) \):**
\[
f(-7) = 4(-7) + 3 = -28 + 3 = -25
\]
(d) **Finding \( f\left(\frac{1}{2}\right) \):**
\[
f\left(\frac{1}{2}\right) = 4\left(\frac{1}{2}\right) + 3 = 2 + 3 = 5
\]
(e) **Finding \( f\left(-\frac{1}{5}\right) \):**
\[
f\left(-\frac{1}{5}\right) = 4\left(-\frac{1}{5}\right) + 3 = -\frac{4}{5} + 3 = -\frac{4}{5} + \frac{15}{5} = \frac{11}{5}
\]
### Final results:
- \( f(5) = 23 \)
- \( f(0) = 3 \)
- \( f(-7) = -25 \)
- \( f\left(\frac{1}{2}\right) = 5 \)
- \( f\left(-\frac{1}{5}\right) = \frac{11}{5} \)
If there is an error or something specific you would like to understand more clearly, please let me know!
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