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For the function​ f, find​ (a) ​f(5​), ​(b) ​f(0​), ​(c) ​f(minus7​), ​(d) f left parenthesis one half right parenthesis

​, and​ (e) f left parenthesis negative one fifth right parenthesis
.
​f(x)equals4xplus3

literal question is f(1/2)=what

3 answers

To evaluate the function \( f(x) = 4x + 3 \) for the various values of \( x \), we will substitute each value into the function.

(a) To find \( f(5) \): \[ f(5) = 4(5) + 3 = 20 + 3 = 23 \]

(b) To find \( f(0) \): \[ f(0) = 4(0) + 3 = 0 + 3 = 3 \]

(c) To find \( f(-7) \): \[ f(-7) = 4(-7) + 3 = -28 + 3 = -25 \]

(d) To find \( f\left(\frac{1}{2}\right) \): \[ f\left(\frac{1}{2}\right) = 4\left(\frac{1}{2}\right) + 3 = 2 + 3 = 5 \]

(e) To find \( f\left(-\frac{1}{5}\right) \): \[ f\left(-\frac{1}{5}\right) = 4\left(-\frac{1}{5}\right) + 3 = -\frac{4}{5} + 3 = -\frac{4}{5} + \frac{15}{5} = \frac{11}{5} \]

In summary:

  • \( f(5) = 23 \)
  • \( f(0) = 3 \)
  • \( f(-7) = -25 \)
  • \( f\left(\frac{1}{2}\right) = 5 \)
  • \( f\left(-\frac{1}{5}\right) = \frac{11}{5} \)
no

I apologize if my response didn't meet your expectations. Let’s go through the evaluations of the function \( f(x) = 4x + 3 \) step-by-step once more.

(a) Finding \( f(5) \): \[ f(5) = 4(5) + 3 = 20 + 3 = 23 \]

(b) Finding \( f(0) \): \[ f(0) = 4(0) + 3 = 0 + 3 = 3 \]

(c) Finding \( f(-7) \): \[ f(-7) = 4(-7) + 3 = -28 + 3 = -25 \]

(d) Finding \( f\left(\frac{1}{2}\right) \): \[ f\left(\frac{1}{2}\right) = 4\left(\frac{1}{2}\right) + 3 = 2 + 3 = 5 \]

(e) Finding \( f\left(-\frac{1}{5}\right) \): \[ f\left(-\frac{1}{5}\right) = 4\left(-\frac{1}{5}\right) + 3 = -\frac{4}{5} + 3 = -\frac{4}{5} + \frac{15}{5} = \frac{11}{5} \]

Final results:

  • \( f(5) = 23 \)
  • \( f(0) = 3 \)
  • \( f(-7) = -25 \)
  • \( f\left(\frac{1}{2}\right) = 5 \)
  • \( f\left(-\frac{1}{5}\right) = \frac{11}{5} \)

If there is an error or something specific you would like to understand more clearly, please let me know!