Question

Which correctly shows the area formula for a trapezoid, A = 2h (b + bz), rearranged for the
quantity of interest h? (1 point)
01 =
2A
h
- 02
0 h = 14(01 + +b2)
0 h = b,+b2
Oh=
2A
b1+b2

Answer 1

To rearrange the area formula for a trapezoid, \( A = \frac{1}{2} h (b_1 + b_2) \), for \( h \), we can follow these steps:

1. Start with the trapezoid area formula:
\[
A = \frac{1}{2} h (b_1 + b_2)
\]

2. Multiply both sides by 2 to eliminate the fraction:
\[
2A = h (b_1 + b_2)
\]

3. Divide both sides by \( (b_1 + b_2) \) to isolate \( h \):
\[
h = \frac{2A}{b_1 + b_2}
\]

Therefore, the correct formula for \( h \) is:
\[
h = \frac{2A}{b_1 + b_2}
\]

Looking at your options, the correct choice is:
\[
h = \frac{2A}{b_1 + b_2}
\]