Question

Which correctly shows the area formula for a trapezoid, A = 1/2 * h(b_{1} + b_{2}) rearranged for the quantity of interest h? (1 point) h = (2A)/(b_{1} + b_{2}) h = 1/2 * A(b_{1} + b_{2}) h = (b_{1} + b_{2})/(2A) b_{1} = (2A)/h - b_{2}

Answer 1

To rearrange the area formula for a trapezoid, \( A = \frac{1}{2} h (b_1 + b_2) \), to solve for \( h \), we can follow these steps:

1. Multiply both sides by 2 to eliminate the fraction:
\[ 2A = h(b_1 + b_2) \]

2. Now, divide both sides by \((b_1 + b_2)\) to isolate \( h \):
\[ h = \frac{2A}{b_1 + b_2} \]

Thus, the correct rearranged formula for \( h \) is:
\[ h = \frac{2A}{b_1 + b_2} \]

So the correct answer is:
**h = (2A)/(b_{1} + b_{2})**.