Question

Two teams are playing tug of war. The tables show the members of each team and how much pulling force each team member applies to the rope.

Team A

Members

Pulling Force

(N)

Darlene 360
Eric 400
Keshawn 450
Team B

Members

Pulling Force

(N)

Anita 350
Frank 390
Molly 490
If Team A pulls to the right and Team B pulls to the left, what is the total horizontal net force applied to the rope?

(1 point)
Responses

40 N to the right
40 N to the right

20 N to the right
20 N to the right

40 N to the left
40 N to the left

20 N to the left
20 N to the left

Answer 1

To find the total horizontal net force applied to the rope, we need to calculate the total pulling force for each team and then find the difference.

**Team A's total pulling force:**
- Darlene: 360 N
- Eric: 400 N
- Keshawn: 450 N

Total for Team A = 360 N + 400 N + 450 N = 1210 N

**Team B's total pulling force:**
- Anita: 350 N
- Frank: 390 N
- Molly: 490 N

Total for Team B = 350 N + 390 N + 490 N = 1230 N

Now, let's calculate the net force:

Net Force = Team A's total force - Team B's total force
Net Force = 1210 N (to the right) - 1230 N (to the left)

Since Team B is greater, we have:

Net Force = 1210 N - 1230 N = -20 N

The negative sign indicates that the net force is directed towards Team B, which is to the left.

Therefore, the total horizontal net force applied to the rope is:

**20 N to the left**.