To complete the last cell, we can use Newton's second law of motion, which states that \( F = m \cdot a \), where \( F \) is the net force, \( m \) is the mass, and \( a \) is the acceleration.
Let's analyze the data provided:
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Net Force (N) = 5.0, Mass (kg) = 5.0, Acceleration (m/s²) = 1.0 \[ F = m \cdot a \implies 5.0 = 5.0 \cdot 1.0 \]
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Net Force (N) = 10.0, Mass (kg) = 5.0, Acceleration (m/s²) = 2.0 \[ F = m \cdot a \implies 10.0 = 5.0 \cdot 2.0 \]
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Net Force (N) = 20.0, Mass (kg) = 5.0, Acceleration (m/s²) = ? \[ F = m \cdot a \implies 20.0 = 5.0 \cdot a \implies a = \frac{20.0}{5.0} = 4.0 , \text{m/s}² \]
Therefore, the acceleration when the net force is 20.0 N and the mass is 5.0 kg is 4.0 m/s².
So, the value that would complete the last cell is 4.0.