Question
Acceleration Quick Check 2 of 52 of 5 Items Question Use the data table to answer the question. It shows the acceleration of a body when a net force is applied to it. Net force (N) Mass (kg) Acceleration (m/s2) 5.0 5.0 1.0 10.0 5.0 2.0 20.0 5.0 Which value would complete the last cell? (1 point) Responses 100.0 100.0 25.0 25.0 4.0 4.0 3.0 3.0 Skip to navigation
Answers
GPT-4o mini
To find the acceleration when a net force of 20.0 N is applied to a mass of 5.0 kg, we can use Newton's second law of motion, which states that:
\[ F = m \cdot a \]
Where:
- \( F \) is the net force applied,
- \( m \) is the mass of the object,
- \( a \) is the acceleration.
From the information given in the data table:
1. For the first row:
- Net Force = 5.0 N, Mass = 5.0 kg
- Using \( F = m \cdot a \): \( a = \frac{F}{m} = \frac{5.0\,N}{5.0\,kg} = 1.0\,m/s^2 \)
2. For the second row:
- Net Force = 10.0 N, Mass = 5.0 kg
- \( a = \frac{10.0\,N}{5.0\,kg} = 2.0\,m/s^2 \)
3. For the third row:
- Net Force = 20.0 N, Mass = 5.0 kg
- \( a = \frac{20.0\,N}{5.0\,kg} = 4.0\,m/s^2 \)
So, the last cell's value for acceleration when the net force is 20.0 N would be **4.0 m/s²**.
The correct response is: **4.0**.
\[ F = m \cdot a \]
Where:
- \( F \) is the net force applied,
- \( m \) is the mass of the object,
- \( a \) is the acceleration.
From the information given in the data table:
1. For the first row:
- Net Force = 5.0 N, Mass = 5.0 kg
- Using \( F = m \cdot a \): \( a = \frac{F}{m} = \frac{5.0\,N}{5.0\,kg} = 1.0\,m/s^2 \)
2. For the second row:
- Net Force = 10.0 N, Mass = 5.0 kg
- \( a = \frac{10.0\,N}{5.0\,kg} = 2.0\,m/s^2 \)
3. For the third row:
- Net Force = 20.0 N, Mass = 5.0 kg
- \( a = \frac{20.0\,N}{5.0\,kg} = 4.0\,m/s^2 \)
So, the last cell's value for acceleration when the net force is 20.0 N would be **4.0 m/s²**.
The correct response is: **4.0**.