Question
Are the growths of the functions f(x) = sinx and g(x) = -sin(-x) the same or different
Answers
GPT-4o mini
To analyze the growths of the functions \( f(x) = \sin(x) \) and \( g(x) = -\sin(-x) \), we should first simplify \( g(x) \).
Using the property of the sine function, we know that \( \sin(-x) = -\sin(x) \). Therefore:
\[
g(x) = -\sin(-x) = -(-\sin(x)) = \sin(x)
\]
So,
\[
g(x) = \sin(x)
\]
Now we can see that:
- \( f(x) = \sin(x) \)
- \( g(x) = \sin(x) \)
Both functions are identical, which means they have the same growth behavior.
Thus, the growths of the functions \( f(x) \) and \( g(x) \) are the same.
Using the property of the sine function, we know that \( \sin(-x) = -\sin(x) \). Therefore:
\[
g(x) = -\sin(-x) = -(-\sin(x)) = \sin(x)
\]
So,
\[
g(x) = \sin(x)
\]
Now we can see that:
- \( f(x) = \sin(x) \)
- \( g(x) = \sin(x) \)
Both functions are identical, which means they have the same growth behavior.
Thus, the growths of the functions \( f(x) \) and \( g(x) \) are the same.