sum of 3 radical 16 and 4 radical 6

To simplify the expression \(3\sqrt{16} + 4\sqrt{6}\), we first evaluate \(\sqrt{16}\):

\[ \sqrt{16} = 4 \]

Substituting this back into the expression gives:

\[ 3\sqrt{16} = 3 \times 4 = 12 \]

Now, substitute this into the original expression:

\[ 3\sqrt{16} + 4\sqrt{6} = 12 + 4\sqrt{6} \]

Thus, the final result is:

\[ 12 + 4\sqrt{6} \]