Question
Express the prime factorization of 1,200 as a product of prime numbers with exponents.(2 points)
blank to the power of 4 dot in the middle blank dot in the middle blank to the power of 2 =1,200
blank to the power of 4 dot in the middle blank dot in the middle blank to the power of 2 =1,200
Answers
Answered by
GPT-4o mini
To express the prime factorization of 1,200, we first break it down into its prime factors.
1. Start by dividing by 2 (the smallest prime number):
- 1200 ÷ 2 = 600
- 600 ÷ 2 = 300
- 300 ÷ 2 = 150
- 150 ÷ 2 = 75
2. Now, divide by 3 (the next smallest prime number):
- 75 ÷ 3 = 25
3. Finally, divide by 5:
- 25 ÷ 5 = 5
- 5 ÷ 5 = 1
So, the prime factorization of 1,200 can be collected as:
- \( 2^4 \) (since 2 was used 4 times)
- \( 3^1 \) (since 3 was used once)
- \( 5^2 \) (since 5 was also used 2 times)
Putting this all together, the prime factorization of 1,200 is:
\[ 2^4 \cdot 3^1 \cdot 5^2 \]
Thus, the answer is:
\[ 2^4 \cdot 3^1 \cdot 5^2 = 1200 \]
1. Start by dividing by 2 (the smallest prime number):
- 1200 ÷ 2 = 600
- 600 ÷ 2 = 300
- 300 ÷ 2 = 150
- 150 ÷ 2 = 75
2. Now, divide by 3 (the next smallest prime number):
- 75 ÷ 3 = 25
3. Finally, divide by 5:
- 25 ÷ 5 = 5
- 5 ÷ 5 = 1
So, the prime factorization of 1,200 can be collected as:
- \( 2^4 \) (since 2 was used 4 times)
- \( 3^1 \) (since 3 was used once)
- \( 5^2 \) (since 5 was also used 2 times)
Putting this all together, the prime factorization of 1,200 is:
\[ 2^4 \cdot 3^1 \cdot 5^2 \]
Thus, the answer is:
\[ 2^4 \cdot 3^1 \cdot 5^2 = 1200 \]