Question

what is the value of the function y = 1/8x - 13 when x = -4?

Answer 1

To find the value of the function \( y = \frac{1}{8}x - 13 \) when \( x = -4 \), we can substitute \(-4\) into the function.

\[
y = \frac{1}{8}(-4) - 13
\]

Now, calculate \(\frac{1}{8}(-4)\):

\[
\frac{1}{8}(-4) = -\frac{4}{8} = -\frac{1}{2}
\]

Now substitute this value back into the equation:

\[
y = -\frac{1}{2} - 13
\]

To combine these terms, we can write \( -13 \) as \( -\frac{26}{2} \):

\[
y = -\frac{1}{2} - \frac{26}{2} = -\frac{1 + 26}{2} = -\frac{27}{2}
\]

Thus, the value of the function when \( x = -4 \) is:

\[
y = -\frac{27}{2} \quad \text{or } -13.5
\]