Asked by jason
Ammonium carbonate decomposes upon heating according to the following balanced equation:
(NH4)2CO3(s)-->2 NH3(g)+CO2(g)+H2O(g)
Calculate the total volume of gas produced at 25 C and 1.07atm by the complete decomposition of 11.86 g of ammonium carbonate.
(NH4)2CO3(s)-->2 NH3(g)+CO2(g)+H2O(g)
Calculate the total volume of gas produced at 25 C and 1.07atm by the complete decomposition of 11.86 g of ammonium carbonate.
Answers
Answered by
DrBob222
1. You have the balanced equation.
2. Convert 11.86 g (NH4)2CO3 t moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles (NH4)2CO3 to
a. moles NH3,
b. moles CO2,
c. moles H2O.
4. Use PV = nRT with total moles = n.
Check my thinking.
2. Convert 11.86 g (NH4)2CO3 t moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles (NH4)2CO3 to
a. moles NH3,
b. moles CO2,
c. moles H2O.
4. Use PV = nRT with total moles = n.
Check my thinking.
Answered by
jason
how do you convert the moles of nh3 co2 ang h2o? is it just 2 mol nh3 1 mol co2 and 1 mol h20?
Answered by
DrBob222
moles (NH4)2CO3 = 11.86/78.048 = about 0.15
Convert moles (NH4)2CO3 to moles CO2.
0.15 mols (NH4)2CO3 x (1 mol CO2/1 mol (NH4)2CO3 = 0.15 x (1/1) = etc.
Convert moles (NH4)2CO3 to moles CO2.
0.15 mols (NH4)2CO3 x (1 mol CO2/1 mol (NH4)2CO3 = 0.15 x (1/1) = etc.
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