Question
Metal Density (g/cm3)
aluminum 2.70
zinc 7.14
iron 7.87
copper 8.96
silver 10.49
lead 11.34
mercury 13.55
gold 19.32
12
What is the identity of a sample that has a mass of 25.0 g and a volume of 2.38 cm3?
A.
aluminum
B.
lead
C.
iron
D.
silver
aluminum 2.70
zinc 7.14
iron 7.87
copper 8.96
silver 10.49
lead 11.34
mercury 13.55
gold 19.32
12
What is the identity of a sample that has a mass of 25.0 g and a volume of 2.38 cm3?
A.
aluminum
B.
lead
C.
iron
D.
silver
Answers
Answered by
GPT-4o mini
To identify the metal sample, we can calculate its density using the formula:
\[
\text{Density} = \frac{\text{mass}}{\text{volume}}
\]
Given:
- Mass = 25.0 g
- Volume = 2.38 cm³
Now, we can calculate the density:
\[
\text{Density} = \frac{25.0 \, \text{g}}{2.38 \, \text{cm}^3} \approx 10.50 \, \text{g/cm}^3
\]
Now, let's compare this calculated density to the densities of the metals provided:
- Aluminum: 2.70 g/cm³
- Zinc: 7.14 g/cm³
- Iron: 7.87 g/cm³
- Copper: 8.96 g/cm³
- Silver: 10.49 g/cm³
- Lead: 11.34 g/cm³
- Mercury: 13.55 g/cm³
- Gold: 19.32 g/cm³
The calculated density of approximately 10.50 g/cm³ is very close to that of silver, which is 10.49 g/cm³. Therefore, it seems that the identity of the sample is:
**D. silver**
\[
\text{Density} = \frac{\text{mass}}{\text{volume}}
\]
Given:
- Mass = 25.0 g
- Volume = 2.38 cm³
Now, we can calculate the density:
\[
\text{Density} = \frac{25.0 \, \text{g}}{2.38 \, \text{cm}^3} \approx 10.50 \, \text{g/cm}^3
\]
Now, let's compare this calculated density to the densities of the metals provided:
- Aluminum: 2.70 g/cm³
- Zinc: 7.14 g/cm³
- Iron: 7.87 g/cm³
- Copper: 8.96 g/cm³
- Silver: 10.49 g/cm³
- Lead: 11.34 g/cm³
- Mercury: 13.55 g/cm³
- Gold: 19.32 g/cm³
The calculated density of approximately 10.50 g/cm³ is very close to that of silver, which is 10.49 g/cm³. Therefore, it seems that the identity of the sample is:
**D. silver**