Question
Metal Density (g/cm3)
aluminum 2.70
zinc 7.14
iron 7.87
copper 8.96
silver 10.49
lead 11.34
mercury 13.55
gold 19.32
9
What is the identity of a sample that has a volume of 92.5 cm3 and a mass of 249.8 g?
A.
zinc
B.
aluminum
C.
gold
D.
iron
aluminum 2.70
zinc 7.14
iron 7.87
copper 8.96
silver 10.49
lead 11.34
mercury 13.55
gold 19.32
9
What is the identity of a sample that has a volume of 92.5 cm3 and a mass of 249.8 g?
A.
zinc
B.
aluminum
C.
gold
D.
iron
Answers
Answered by
GPT-4o mini
To identify the sample, we first need to calculate its density using the formula:
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
Given:
- Mass = 249.8 g
- Volume = 92.5 cm³
Calculating the density:
\[
\text{Density} = \frac{249.8 \text{ g}}{92.5 \text{ cm}^3} \approx 2.70 \text{ g/cm}^3
\]
Now we can compare the calculated density with the densities provided for each metal:
- Aluminum: 2.70 g/cm³
- Zinc: 7.14 g/cm³
- Iron: 7.87 g/cm³
- Copper: 8.96 g/cm³
- Silver: 10.49 g/cm³
- Lead: 11.34 g/cm³
- Mercury: 13.55 g/cm³
- Gold: 19.32 g/cm³
The calculated density of approximately 2.70 g/cm³ matches the density of aluminum.
Therefore, the identity of the sample is:
**B. aluminum**
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
Given:
- Mass = 249.8 g
- Volume = 92.5 cm³
Calculating the density:
\[
\text{Density} = \frac{249.8 \text{ g}}{92.5 \text{ cm}^3} \approx 2.70 \text{ g/cm}^3
\]
Now we can compare the calculated density with the densities provided for each metal:
- Aluminum: 2.70 g/cm³
- Zinc: 7.14 g/cm³
- Iron: 7.87 g/cm³
- Copper: 8.96 g/cm³
- Silver: 10.49 g/cm³
- Lead: 11.34 g/cm³
- Mercury: 13.55 g/cm³
- Gold: 19.32 g/cm³
The calculated density of approximately 2.70 g/cm³ matches the density of aluminum.
Therefore, the identity of the sample is:
**B. aluminum**