Question
C7H6O3+CH3OH→C8H8O3+H2O
In any experiment, 1.50g of salicyclic acid is reacted with 11.20g of methanol. The yield of methyl salicylate, C8H8O3, is 1.31g. What is the percent yield?
percent is 77.l1%
is this correct?
In any experiment, 1.50g of salicyclic acid is reacted with 11.20g of methanol. The yield of methyl salicylate, C8H8O3, is 1.31g. What is the percent yield?
percent is 77.l1%
is this correct?
Answers
bobpursley
theoretical yield= 1.50/molmassC7H6O3 * molmassC8H8OH
=1.50/138.12 * 152.14=1.65g
percent yield= 1.31/1.65=.792
check my calcs.
=1.50/138.12 * 152.14=1.65g
percent yield= 1.31/1.65=.792
check my calcs.