1. Writ and balance the equation.
2. Convert 11.2 g methanol to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles methanol to moles of the product.
4. Now convert moles of the product to grams. g = moles x molar mass. This is the theoretical yield.
5. %yield = (actual yield/theoretical yield)*100 = ??
C7H6O3+CH3OH→C8H8O3+H2O
In any experiment, 1.50g of salicyclic acid is reacted with 11.20g of methanol. The yield of methyl salicylate, C8H8O3, is 1.31g. What is the percent yield?
2 answers
From my understanding the equation is already balanced, correct?
My answer: 26.7%, is this correct?
Work: (11.20gCH3OH)(1 mol CH3OH)/32.05gCH3OH=0.3495gCH3OH
0.3495g/1.31g= 26.68%
My answer: 26.7%, is this correct?
Work: (11.20gCH3OH)(1 mol CH3OH)/32.05gCH3OH=0.3495gCH3OH
0.3495g/1.31g= 26.68%
3 answers