Asked by bme1

Calculate the molarity (mol/L) of Ba2+ when BaCrO4 is placed in a 0.0457 M K2CrO4 solution. The equation represents the solubility process. K(sp)=1.2x10^-10

BaCrO4 (s) Ba2+ (aq) + CrO42- (aq)

15 years ago

Answered by bme1

BaCrO4 (s)= Ba2+ (aq) + CrO42- (aq)

15 years ago

Answered by DrBob222

Ksp = (Ba^+2)(CrO4^-2)
You know Ksp. You know molarity CrO4. Calculate molarity Ba^+2.

15 years ago

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