Asked by Jazz
Calculate the molarity of 1.77 mol of LiCl in 30.6 L of solution.
This is for hw that's submitted online. the answer i got is 0.06 M. but it says its wrong, whyyyyy?
This is for hw that's submitted online. the answer i got is 0.06 M. but it says its wrong, whyyyyy?
Answers
Answered by
jai
molarity is moles of solute per liter of solution:
M = moles/L
plug in the given values in the equation, therefore:
M = 1.77 / 30.6 = 0.0578 M
is it required to write the answer in correct number of significant figures?
if not, i think 0.06 M is acceptable ;
but if yes, it must be 0.0578 M (3 significant figures),,
hope this helps.
M = moles/L
plug in the given values in the equation, therefore:
M = 1.77 / 30.6 = 0.0578 M
is it required to write the answer in correct number of significant figures?
if not, i think 0.06 M is acceptable ;
but if yes, it must be 0.0578 M (3 significant figures),,
hope this helps.
Answered by
DrBob222
jai is correct. Most of these on-line databases require the correct number of significant figures and 0.06 will be counted wrong.
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