dentify the​ vertex, the axis of​ symmetry, the maximum or minimum​ value, and the range of the parabola.yequalsxsquaredplus2xplus5Question content area bottomPart 1The vertex isenter your response here. ​(Type an ordered​ pair.)

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To find the vertex, axis of symmetry, maximum or minimum value, and range of the parabola given by the equation \( y = x^2 + 2x + 5 \), we can follow these steps:

  1. Finding the vertex: The vertex form of a quadratic equation can be determined using the formula: \[ x = -\frac{b}{2a} \] where \( a \) is the coefficient of \( x^2 \) and \( b \) is the coefficient of \( x \).

    In the equation \( y = x^2 + 2x + 5 \):

    • \( a = 1 \)
    • \( b = 2 \)

    Now, substituting in the values: \[ x = -\frac{2}{2 \cdot 1} = -1 \]

    Next, substitute \( x = -1 \) back into the equation to find the \( y \)-coordinate of the vertex: \[ y = (-1)^2 + 2(-1) + 5 = 1 - 2 + 5 = 4 \]

    Thus, the vertex is: \[ \text{Vertex} = (-1, 4) \]

  2. Axis of symmetry: The axis of symmetry is the vertical line that passes through the vertex. This can be given by the equation: \[ x = -1 \]

  3. Maximum or minimum value: Since the coefficient of \( x^2 \) (which is \( a = 1 \)) is positive, the parabola opens upwards. Therefore, the vertex represents the minimum point of the parabola.

    Minimum value of \( y \): \[ \text{Minimum value} = 4 \]

  4. Range of the parabola: Since the parabola opens upwards and the minimum value is 4, the range of the function is: \[ \text{Range} = [4, \infty) \]

Final Results:

  • Vertex: \( (-1, 4) \)
  • Axis of symmetry: \( x = -1 \)
  • Minimum value: \( 4 \)
  • Range: \( [4, \infty) \)