To determine how many solutions there are for the equations \(3y = 3x + 6\) and \(y = x + 2\), we should first rewrite both equations in slope-intercept form (\(y = mx + b\)) for easier comparison.
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First equation: \[ 3y = 3x + 6 \] Dividing all terms by 3: \[ y = x + 2 \]
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Second equation: \[ y = x + 2 \]
Now we see that both equations simplify to the same equation: \[ y = x + 2 \]
Since both equations represent the same line, they have an infinite number of solutions (every point on the line is a solution).
Thus, the answer is Infinite solutions.