Asked by bigepic
This graph shows the lines for these equations:
3y=3x + 6
y = x + 2
How many solutions are there for this system of equations?
3y=3x + 6
y = x + 2
How many solutions are there for this system of equations?
Answers
Answered by
bigepic
The table shows a linear relationship between the variables x and y.
x y
5 16.5
7 21.5
11 31.5
What are the slope and y-intercept of the linear relationship?
x y
5 16.5
7 21.5
11 31.5
What are the slope and y-intercept of the linear relationship?
Answered by
GPT-4o mini
To determine how many solutions there are for the system of equations represented by the lines \(3y = 3x + 6\) and \(y = x + 2\), we can start by rewriting the first equation in the slope-intercept form (y = mx + b).
1. Start with the equation \(3y = 3x + 6\).
2. Divide every term by 3 to solve for \(y\):
\[
y = x + 2
\]
Now we have both equations for the lines:
1. \(y = x + 2\) (from the first equation)
2. \(y = x + 2\) (the second equation)
Both equations are the same: \(y = x + 2\).
Since these two lines are identical, they overlap completely. This means that there are infinitely many solutions to this system of equations, as every point on the line is a solution.
**Conclusion: There are infinitely many solutions.**
1. Start with the equation \(3y = 3x + 6\).
2. Divide every term by 3 to solve for \(y\):
\[
y = x + 2
\]
Now we have both equations for the lines:
1. \(y = x + 2\) (from the first equation)
2. \(y = x + 2\) (the second equation)
Both equations are the same: \(y = x + 2\).
Since these two lines are identical, they overlap completely. This means that there are infinitely many solutions to this system of equations, as every point on the line is a solution.
**Conclusion: There are infinitely many solutions.**
Answered by
GPT-4o mini
To find the slope and y-intercept of the linear relationship between \(x\) and \(y\), we can use the points provided in the table:
- (5, 16.5)
- (7, 21.5)
- (11, 31.5)
### Step 1: Calculate the slope (m)
The formula for the slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Let's use the points (5, 16.5) and (7, 21.5):
1. \(x_1 = 5\), \(y_1 = 16.5\)
2. \(x_2 = 7\), \(y_2 = 21.5\)
Substituting these values into the slope formula:
\[
m = \frac{21.5 - 16.5}{7 - 5} = \frac{5}{2} = 2.5
\]
### Step 2: Calculate the y-intercept (b)
We can use the slope-point form of the equation of a line:
\[
y = mx + b
\]
We already know the slope \(m = 2.5\). We'll use one of the points to solve for \(b\). Let's use the point (5, 16.5):
\[
16.5 = 2.5(5) + b
\]
Calculating \(2.5(5)\):
\[
16.5 = 12.5 + b
\]
Now isolate \(b\):
\[
b = 16.5 - 12.5 = 4
\]
### Conclusion
The slope of the linear relationship is \(m = 2.5\) and the y-intercept is \(b = 4\).
So, the final results are:
- **Slope (m)**: 2.5
- **Y-intercept (b)**: 4
The equation of the line is:
\[
y = 2.5x + 4
\]
- (5, 16.5)
- (7, 21.5)
- (11, 31.5)
### Step 1: Calculate the slope (m)
The formula for the slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Let's use the points (5, 16.5) and (7, 21.5):
1. \(x_1 = 5\), \(y_1 = 16.5\)
2. \(x_2 = 7\), \(y_2 = 21.5\)
Substituting these values into the slope formula:
\[
m = \frac{21.5 - 16.5}{7 - 5} = \frac{5}{2} = 2.5
\]
### Step 2: Calculate the y-intercept (b)
We can use the slope-point form of the equation of a line:
\[
y = mx + b
\]
We already know the slope \(m = 2.5\). We'll use one of the points to solve for \(b\). Let's use the point (5, 16.5):
\[
16.5 = 2.5(5) + b
\]
Calculating \(2.5(5)\):
\[
16.5 = 12.5 + b
\]
Now isolate \(b\):
\[
b = 16.5 - 12.5 = 4
\]
### Conclusion
The slope of the linear relationship is \(m = 2.5\) and the y-intercept is \(b = 4\).
So, the final results are:
- **Slope (m)**: 2.5
- **Y-intercept (b)**: 4
The equation of the line is:
\[
y = 2.5x + 4
\]