To solve the expression \( 10 \cdot 6 + 3 \cdot 3 \div 2 + 6 \), we follow the order of operations (PEMDAS/BODMAS).
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Start with the multiplication and division from left to right:
- \( 10 \cdot 6 = 60 \)
- \( 3 \cdot 3 = 9 \)
- Now divide: \( 9 \div 2 = 4.5 \)
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Now substitute the results back into the expression:
- \( 60 + 4.5 + 6 \)
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Finally, perform the addition:
- \( 60 + 4.5 = 64.5 \)
- Now add \( 6 \): \( 64.5 + 6 = 70.5 \)
Thus, the result of the expression \( 10 \cdot 6 + 3 \cdot 3 \div 2 + 6 \) is \( 70.5 \).