To determine if the point (3, 8) is a solution to the simultaneous inequalities \( y > x + 5 \) and \( y \leq 6x - 3 \), we need to check if the point satisfies both inequalities.
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Check the first inequality \( y > x + 5 \): Plugging in \( x = 3 \) and \( y = 8 \): \[ 8 > 3 + 5 \] \[ 8 > 8 \] This is false since 8 is not greater than 8. Therefore, (3, 8) does not satisfy this inequality.
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Check the second inequality \( y \leq 6x - 3 \): Plugging in \( x = 3 \) and \( y = 8 \): \[ 8 \leq 6(3) - 3 \] \[ 8 \leq 18 - 3 \] \[ 8 \leq 15 \] This is true.
Since (3, 8) satisfies the inequality \( y \leq 6x - 3 \) but does not satisfy the inequality \( y > x + 5 \), we conclude that:
The correct response is: No, it is in the solution set for \( y \leq 6x - 3 \), but on the line for \( y > x + 5 \).