Let's define the linear equations based on the given costs for each bowling alley.
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For Bowl-O-Rama: The cost \( C \) to bowl at Bowl-O-Rama is given by: \[ C = 5g + 4 \] where \( g \) is the number of games played.
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For Bowling Pinz: The cost \( C \) to bowl at Bowling Pinz is given by: \[ C = 4g + 8 \]
So, the pair of linear equations that model this situation are:
- Equation to represent the cost at Bowl-O-Rama: \(\ C = 5g + 4 \)
- Equation to represent the cost at Bowling Pinz: \(\ C = 4g + 8 \)
If you need to find where these costs are equal (i.e., when the costs are the same for a given number of games), you can set the equations equal to each other and solve for \( g \): \[ 5g + 4 = 4g + 8 \]
Subtract \( 4g \) from both sides: \[ 5g - 4g + 4 = 8 \]
This simplifies to: \[ g + 4 = 8 \]
Now, subtract 4 from both sides: \[ g = 4 \]
So, the costs are equal when 4 games are bowled. To find the cost at this number of games, substitute \( g = 4 \) into either equation:
- Using Bowl-O-Rama's equation: \[ C = 5(4) + 4 = 20 + 4 = 24 \]
- Using Bowling Pinz's equation: \[ C = 4(4) + 8 = 16 + 8 = 24 \]
Both equations give the same cost of \( C = 24 \) when \( g = 4 \).
If you need further clarification or another part of the response, feel free to ask!