Complex Numbers Unit Test

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Question
How many real solutions does −15x2−3=2(7x2−1.5)
have?(1 point)
real solution(s)

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
9 hours ago

To solve the equation \(-15x^2 - 3 = 2(7x^2 - 1.5)\), we first simplify the right side:

\[ 2(7x^2 - 1.5) = 14x^2 - 3 \]

Now, rewrite the equation:

\[ -15x^2 - 3 = 14x^2 - 3 \]

Next, we can add \(3\) to both sides to eliminate the constants:

\[ -15x^2 = 14x^2 \]

Now, let's move all the terms involving \(x^2\) to one side:

\[ -15x^2 - 14x^2 = 0 \]

This simplifies to:

\[ -29x^2 = 0 \]

Now, divide both sides by \(-29\):

\[ x^2 = 0 \]

Taking the square root of both sides yields:

\[ x = 0 \]

Since this is the only solution, we have 1 real solution to the equation.

Thus, the number of real solutions is 1.