Asked by blobby
Complex Numbers Unit Test
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Question
Solve the equation −x2−3x=5−3x
and re-express the answer as a complex number with the imaginary unit.(1 point)
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Answers
Answered by
GPT-4o mini
To solve the equation \(-x^2 - 3x = 5 - 3x\), we can start by simplifying it.
First, let's move all terms to one side so that we have zero on one side:
\[
-x^2 - 3x - 5 + 3x = 0
\]
This simplifies to:
\[
-x^2 - 5 = 0
\]
Next, we can multiply through by -1 to make it easier to work with:
\[
x^2 + 5 = 0
\]
Now, we subtract 5 from both sides:
\[
x^2 = -5
\]
To find \(x\), we take the square root of both sides:
\[
x = \pm \sqrt{-5}
\]
Using the imaginary unit \(i\), where \(i = \sqrt{-1}\), we can express the solutions as:
\[
x = \pm \sqrt{5}i
\]
Thus, the solutions to the equation \(-x^2 - 3x = 5 - 3x\) expressed as complex numbers are:
\[
x = \sqrt{5}i \quad \text{and} \quad x = -\sqrt{5}i
\]
First, let's move all terms to one side so that we have zero on one side:
\[
-x^2 - 3x - 5 + 3x = 0
\]
This simplifies to:
\[
-x^2 - 5 = 0
\]
Next, we can multiply through by -1 to make it easier to work with:
\[
x^2 + 5 = 0
\]
Now, we subtract 5 from both sides:
\[
x^2 = -5
\]
To find \(x\), we take the square root of both sides:
\[
x = \pm \sqrt{-5}
\]
Using the imaginary unit \(i\), where \(i = \sqrt{-1}\), we can express the solutions as:
\[
x = \pm \sqrt{5}i
\]
Thus, the solutions to the equation \(-x^2 - 3x = 5 - 3x\) expressed as complex numbers are:
\[
x = \sqrt{5}i \quad \text{and} \quad x = -\sqrt{5}i
\]