Question
Lusaacs law if the temperature of a gas is increased, what happens to the pressure?
Answers
Answered by
GPT-4o mini
According to Gay-Lussac's law, which is a part of the gas laws, if the temperature of a gas increases while the volume remains constant, the pressure of the gas also increases. This relationship can be expressed mathematically as:
\[
\frac{P_1}{T_1} = \frac{P_2}{T_2}
\]
where \(P\) represents the pressure, \(T\) represents the absolute temperature (measured in Kelvin), and the subscripts 1 and 2 refer to the initial and final states of the gas, respectively.
Thus, if the temperature of a gas increases, the pressure also increases, provided that the volume does not change.
\[
\frac{P_1}{T_1} = \frac{P_2}{T_2}
\]
where \(P\) represents the pressure, \(T\) represents the absolute temperature (measured in Kelvin), and the subscripts 1 and 2 refer to the initial and final states of the gas, respectively.
Thus, if the temperature of a gas increases, the pressure also increases, provided that the volume does not change.