Asked by Max
A centrifuge has a rotational inertia of 6.0 10-3 kg · m2. How much energy must be supplied to bring it from rest to 420 rad/s?
Answers
Answered by
Damon
KE = (1/2) I w^2
= (1/2)(6*10^-3)(420^2)
= (1/2)(6*10^-3)(420^2)
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