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To solve the compound inequality \(-3 \geq x + 2 \geq -4\), we can split it into two separate inequalities:
1. \(-3 \geq x + 2\)
2. \(x + 2 \geq -4\)
### Step 1: Solve the first inequality \(-3 \geq x + 2\)
Subtract 2 from both sides:
\[
-3 - 2 \geq x
\]
\[
-5 \geq x
\]
or
\[
x \leq -5
\]
### Step 2: Solve the second inequality \(x + 2 \geq -4\)
Subtract 2 from both sides:
\[
x \geq -4 - 2
\]
\[
x \geq -6
\]
### Step 3: Combine the results
So, we have:
- From \(x + 2 \geq -4\), we get \(x \geq -6\).
- From \(-3 \geq x + 2\), we get \(x \leq -5\).
This gives us the combined inequality:
\[
-6 \leq x \leq -5
\]
### Conclusion
The solution to the inequality is:
\[
[-6, -5]
\]
This means \(x\) can take any value from \(-6\) to \(-5\), inclusive.