Asked by anonymous

calculate [h3o] in solutions. 0.040 of HCl and 0.080 HOCl.

2. calculate OH for the solutions of 0.0063 ba (OH)2 and 0.0110 of BaCl2

Answers

Answered by DrBob222
1. This is a buffer solution. Use the Henderson-Hasselbalch equation.

2. This is made to look like a buffer solution but it isn't. Calculate OH from the Ba(OH)2 concn.
Post your work if you get stuck.
Answered by anonymous
thank you. for #1, do i just get the PH and then covert that to H3O then?
Answered by anonymous
but if HCL and HOCl are both strong acids, how can i use the equation? since its supposed to be an acid and base right?
Answered by DrBob222
No. I'm glad you asked the question because it made me look at the problem again. I gave you a bum way to go. This is not a buffered solution, it is the solution of a strong acid (HCl) and a weak acid (HOCl). What you do here is to calculate the H3O^+ from the strong acid, then the H3O^+ from the weak acid, add the moles together and divide by the volume to determine molarity. I suspect, however, that the contribution by HOCl will be very small, perhaps even negligible.
Answered by DrBob222
After reading your second response, HOCl is a weak acid. You can determine the Ka by looking in tables in your text or your notes.
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