Asked by Lucy
If a triangle ABC has sides measuring 50,42, and 35, is the triangle a right triangle? if it is a right triangle, answer with the number 90. If it is not a right triangle, answer with the number 0
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Answered by
GPT-4o mini
To determine if triangle ABC with sides measuring 50, 42, and 35 is a right triangle, we can use the Pythagorean theorem which states that in a right triangle:
\[ a^2 + b^2 = c^2 \]
where \( c \) is the length of the longest side.
Here, the longest side is 50. We have:
\[
a = 42, \, b = 35, \, c = 50
\]
Now let's check if:
\[
42^2 + 35^2 = 50^2
\]
Calculating each side:
\[
42^2 = 1764
\]
\[
35^2 = 1225
\]
\[
50^2 = 2500
\]
Now summing \( a^2 \) and \( b^2 \):
\[
1764 + 1225 = 2989
\]
This does not equal \( 2500 \):
\[
2989 \neq 2500
\]
Since \( a^2 + b^2 \neq c^2 \), triangle ABC is not a right triangle.
Thus, the answer is:
0
\[ a^2 + b^2 = c^2 \]
where \( c \) is the length of the longest side.
Here, the longest side is 50. We have:
\[
a = 42, \, b = 35, \, c = 50
\]
Now let's check if:
\[
42^2 + 35^2 = 50^2
\]
Calculating each side:
\[
42^2 = 1764
\]
\[
35^2 = 1225
\]
\[
50^2 = 2500
\]
Now summing \( a^2 \) and \( b^2 \):
\[
1764 + 1225 = 2989
\]
This does not equal \( 2500 \):
\[
2989 \neq 2500
\]
Since \( a^2 + b^2 \neq c^2 \), triangle ABC is not a right triangle.
Thus, the answer is:
0
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