Question
1) Solve `2x^{2}-5x-3=0`and enter solutions below.
2) Push the "Graph It" Button to see a graph of `y=2x^{2}-5x-3`
Enter solution 1 and 2
2) Push the "Graph It" Button to see a graph of `y=2x^{2}-5x-3`
Enter solution 1 and 2
Answers
GPT-4o mini
To solve the quadratic equation \(2x^{2}-5x-3=0\), we can use the quadratic formula:
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
where \(a = 2\), \(b = -5\), and \(c = -3\).
1) First, we calculate the discriminant (\(b^2 - 4ac\)):
\[
b^2 - 4ac = (-5)^2 - 4(2)(-3) = 25 + 24 = 49
\]
2) Now we can use the quadratic formula:
\[
x = \frac{-(-5) \pm \sqrt{49}}{2(2)} = \frac{5 \pm 7}{4}
\]
3) We find the solutions:
- For the positive case:
\[
x_1 = \frac{5 + 7}{4} = \frac{12}{4} = 3
\]
- For the negative case:
\[
x_2 = \frac{5 - 7}{4} = \frac{-2}{4} = -\frac{1}{2}
\]
Thus, the solutions to the equation \(2x^{2}-5x-3=0\) are:
1. \(x_1 = 3\)
2. \(x_2 = -\frac{1}{2}\)
You can enter these solutions as:
1. \(3\)
2. \(-\frac{1}{2}\)
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
where \(a = 2\), \(b = -5\), and \(c = -3\).
1) First, we calculate the discriminant (\(b^2 - 4ac\)):
\[
b^2 - 4ac = (-5)^2 - 4(2)(-3) = 25 + 24 = 49
\]
2) Now we can use the quadratic formula:
\[
x = \frac{-(-5) \pm \sqrt{49}}{2(2)} = \frac{5 \pm 7}{4}
\]
3) We find the solutions:
- For the positive case:
\[
x_1 = \frac{5 + 7}{4} = \frac{12}{4} = 3
\]
- For the negative case:
\[
x_2 = \frac{5 - 7}{4} = \frac{-2}{4} = -\frac{1}{2}
\]
Thus, the solutions to the equation \(2x^{2}-5x-3=0\) are:
1. \(x_1 = 3\)
2. \(x_2 = -\frac{1}{2}\)
You can enter these solutions as:
1. \(3\)
2. \(-\frac{1}{2}\)